35x^2-43x-36=0

Solution for 35x^2-43x-36=0 equation:

35x^2-43x-36=0

a = 35; b = -43; c = -36;
Δ = b2-4ac
Δ = -432-4·35·(-36)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-83}{2*35}=\frac{-40}{70}
=-4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+83}{2*35}=\frac{126}{70}
=1+4/5
$